Basic Properties of Electric Charges
Where, [In SI, when the two charges are located in vacuum]
− Absolute permittivity of free space = 8.854 × 10−12 C2 N−1 m−2
We can write equation (i) as
The ratio is denoted by εr, which is called relative permittivity of the medium with respect to vacuum. It is also denoted by k, called dielectric constant of the medium.
ε = kε0
Coulomb’s Law in Vector Form
Consider two like charges q1 and q2 present at points A and B in vacuum at a distance r apart.
According to Coulomb’s law, the magnitude of force on charge q1 due to q2 (or on charge q2 due to q1) is given by,
Let
− Unit vector pointing from charge q1 to q2
− Unit vector pointing from charge q2 to q1
[is along the direction of unit vector ] …(ii)
[is along the direction of unit vector] …(iii)
∴Equation (ii) becomes
On comparing equation (iii) with equation (iv), we obtain
Forces between Multiple Charges
Principle of superposition − Force on any charge due to a number of other charges is the vector sum of all the forces on that charge due to the other charges, taken one at a time. The individual forces are unaffected due to the presence of other charges.
Consider that n point charges q1, q2, q3, … qn are distributed in space in a discrete manner. The charges are interacting with each other. Let the charges q2, q3, … qn exert forces on charge q1. Then, according to principle of superposition, the total force on charge q1 is given by,
If the distance between the charges q1 and q2 is denoted as r12; and is unit vector from charge q2 to q1, then
Similarly, the force on charge q1 due to other charges is given by,
Substituting these in equation (i),
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Additive nature of charges − The total electric
charge on an object is equal to the algebraic sum of all the electric
charges distributed on the different parts of the object. If q1, q2, q3, … are electric charges present on different parts of an object, then total electric charge on the object, q = q1 + q2 + q3 + …
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Charge is conserved − When an isolated system
consists of many charged bodies within it, due to interaction among
these bodies, charges may get redistributed. However, it is found that
the total charge of the isolated system is always conserved.
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Quantization of charge − All observable charges are always some integral multiple of elementary charge, e (= ± 1.6 × 10−19 C). This is known as quantization of charge.
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Two point charges attract or repel each other with a force which is
directly proportional to the product of the magnitudes of the charges
and inversely proportional to the square of the distance between them.
Where, [In SI, when the two charges are located in vacuum]
− Absolute permittivity of free space = 8.854 × 10−12 C2 N−1 m−2
We can write equation (i) as
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The force between two charges q1 and q2 located at a distance r in a medium may be expressed as
The ratio is denoted by εr, which is called relative permittivity of the medium with respect to vacuum. It is also denoted by k, called dielectric constant of the medium.
ε = kε0
Coulomb’s Law in Vector Form
Consider two like charges q1 and q2 present at points A and B in vacuum at a distance r apart.
According to Coulomb’s law, the magnitude of force on charge q1 due to q2 (or on charge q2 due to q1) is given by,
Let
− Unit vector pointing from charge q1 to q2
− Unit vector pointing from charge q2 to q1
[is along the direction of unit vector ] …(ii)
[is along the direction of unit vector] …(iii)
∴Equation (ii) becomes
On comparing equation (iii) with equation (iv), we obtain
Forces between Multiple Charges
Principle of superposition − Force on any charge due to a number of other charges is the vector sum of all the forces on that charge due to the other charges, taken one at a time. The individual forces are unaffected due to the presence of other charges.
Consider that n point charges q1, q2, q3, … qn are distributed in space in a discrete manner. The charges are interacting with each other. Let the charges q2, q3, … qn exert forces on charge q1. Then, according to principle of superposition, the total force on charge q1 is given by,
If the distance between the charges q1 and q2 is denoted as r12; and is unit vector from charge q2 to q1, then
Similarly, the force on charge q1 due to other charges is given by,
Substituting these in equation (i),
Electric Field − It is the space around a charge, in which any other charge experiences an electrostatic force.
Electric Field Intensity − The electric field intensity at a point due to a source charge is defined as the force experienced per unit positive test charge placed at that point without disturbing the source charge.
Where,
→ Electric field intensity
Force experienced by the test charge q0
Its SI unit is NC−1.
Electric Field Due To a Point Charge
We have to find electric field at point P due to point charge +q placed at the origin such that
To find the same, place a vanishingly small positive test charge q0 at point P.
According to Coulomb’s law, force on the test charge q0 due to charge q is
If is the electric field at point P, then
The magnitude of the electric field at point P is given by,
Representation of Electric Field
Electric Field Due To a System of Charges
Consider that n point charges q1, q2, q3, … qn exert forces on the test charge placed at origin O.
Let be force due to ith charge qi on q0. Then,
Where, ri is the distance of the test charge q0 from qi
The electric field at the observation point P is given by,
If is the electric field at point P due to the system of charges, then by principal of superposition of electric fields,
Using equation (i), we obtain
Electric Field Lines
An electric line of force is the path along which a unit positive charge would move, if it is free to do so.
Continuous Charge Distribution
Where,
λ → Linear charge density
q → Charge distributed along a line
L → Length of the rod
Where,
σ → Surface charge density
q → Charge distributed on area A
Where,
δ → Volume charge density
V → Volume of the conductor
q → Charge on conductor
Electric Field Intensity − The electric field intensity at a point due to a source charge is defined as the force experienced per unit positive test charge placed at that point without disturbing the source charge.
→ Electric field intensity
Force experienced by the test charge q0
Its SI unit is NC−1.
Electric Field Due To a Point Charge
To find the same, place a vanishingly small positive test charge q0 at point P.
According to Coulomb’s law, force on the test charge q0 due to charge q is
Let be force due to ith charge qi on q0. Then,
Where, ri is the distance of the test charge q0 from qi
The electric field at the observation point P is given by,
An electric line of force is the path along which a unit positive charge would move, if it is free to do so.
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Properties of Electric Lines of Force
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These start from the positive charge and end at the negative charge.
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They always originate or terminate at right angles to the surface of the charge.
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They can never intersect each other because it
will mean that at that particular point, electric field has two
directions. It is not possible.
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They do not pass through a conductor.
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They contract longitudinally.
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They exert a lateral pressure on each other.
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Representation of Electric Field Lines
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Field lines in case of isolated point charges
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Field lines in case of a system of two charges
Continuous Charge Distribution
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Linear charge density − When charge is distributed along a line, the charge distribution is called linear.
λ → Linear charge density
q → Charge distributed along a line
L → Length of the rod
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Surface charge density
σ → Surface charge density
q → Charge distributed on area A
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Volume charge densityThe electric flux, through a surface, held inside an electric field represents the total number of electric lines of force crossing the surface in a direction normal to the surface.
Electric flux is a scalar quantity and is denoted by Φ.
SI unit − Nm2 C−1
Gauss Theorem
It states that the total electric flux through a closed surface enclosing a charge is equal to times the magnitude of the charge enclosed.
However,
∴Gauss theorem may be expressed as
Proof
Consider that a point electric charge q is situated at the centre of a sphere of radius ‘a’.
According to Coulomb’s law,
Where, is unit vector along the line OP
The electric flux through area element is given by,
Therefore, electric flux through the closed surface of the sphere,
It proves the Gauss theorem in electrostatics.
δ → Volume charge density
V → Volume of the conductor
q → Charge on conductor
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